Up to this point:
This week:
Kriegspiel
Sources:
Battle of the Sexes
Rock Paper Scissors
Definitions:
By hand
\[\sigma_\text{Gary}(M) = x\]
\(U_\text{Monica}(\sigma_\text{Gary}, M) = 2x\),
\(U_\text{Monica}(\sigma_\text{Gary}, G) = 1-x\)
If \(x=1/3\), these are equal, so Monica is indifferent. By symmetry, \(\sigma = \{(\frac{2}{3},\frac{1}{3}), (\frac{1}{3},\frac{2}{3}\}\) is a Nash Equilibrium.
For action profile \(\mathbf{a}\), player \(i\)'s regret for not playing action \(a'\) is: \[R(a'_i) = U(a'_i, a_{-i}) - U(\mathbf{a})\] that is, the utility missed out on by not playing \(a'\).
Positive regret means that action would have been better.
Regret Matching:
For some number of iterations:
Terminology
Minimax Tree
MDP Expectimax Tree
\[V(s) = \text{max}_{a \in \mathcal{A}}\left(R(s, a) + \text{E}[V(s')]\right)\]
\[V_1(s) = \text{max}_{a \in \mathcal{A_1}}\left(R(s, a) + \text{min}_{a' \in A_2} (R(s', a') + V(s''))\right)\]
Why is this harder than an MDP? (think back to sparse sampling)
Examples of evaluation functions:
Bonus: what if 5 was not green?
Extensive-form game definition (\(h\) is a sequence of actions called a "history"):
Exponential in number of info states!
3 Cards: 1, 2, and 3
Solution (found by hand in 1950s):