Next Year: emphasize yes/inconclusive d-separation outcome
Bayesian Network: Directed Acyclic Graph (DAG) that represents a joint probability distribution
Random Variable
\(P(X, Y) = P(X)\, P(Y)\)
\(P(X, Y \mid Z) = P(X \mid Z) \, P(Y \mid Z)\)
\[P(x_{1:n}) = \prod_{i=1}^n P(x_i \mid \text{pa}(x_i))\]
All of \(X\)'s dependence on \(Y\) comes through \(Z\)
\(X \perp Y \mid Z\)
\(\implies\)
\(A \perp C \mid B\) ?
Mediator
Yes
\(B \perp C \mid A\) ?
Confounder
Yes
\(B \perp C \mid A\) ?
Collider
Inconclusive
https://kunalmenda.com/2019/02/21/causation-and-correlation/
\((B\perp D \mid A)\) ?
\((B\perp D \mid E)\) ?
Yes!
No
Today: Systematic way to reason about conditional independence
Why is this relevant?
Let \(\mathcal{C}\) be a set of random variables.
A path between \(A\) and \(B\) is d-separated by \(\mathcal{C}\) if any of the following are true
We say that \(A\) and \(B\) are d-separated by \(\mathcal{C}\) if all paths between \(A\) and \(B\) are d-separated by \(\mathcal{C}\).
If \(A\) and \(B\) are d-separated by \(\mathcal{C}\) then \(A \perp B \mid \mathcal{C}\)
Next year: No *descendant* in C (see book)
Example: \((B \perp D \mid C, E)\) ?
\(D \perp C \mid B\) ?
\(D \perp C \mid E\) ?
Given a Bayesian network, how do we sample from the joint distribution it defines?
Analogous to Simulating a (PO)MDP